/* * Copyright 2014 Higher Frequency Trading * * http://www.higherfrequencytrading.com * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ package net.openhft.chronicle.map.example; import net.openhft.chronicle.map.ChronicleMap; import net.openhft.chronicle.map.ChronicleMapBuilder; import net.openhft.lang.model.DataValueClasses; import net.openhft.lang.values.LongValue; import java.io.File; import java.io.IOException; import java.util.Arrays; public class DistributedSequenceMain { public static void main(String... ignored) throws IOException { File file = File.createTempFile("sequence-numbers", ".dat"); try (ChronicleMap map = ChronicleMapBuilder.of(String.class, LongValue.class) .entries(128) .actualSegments(1) .createPersistedTo(file)) { // throughput test. for (int t = 0; t < 5; t++) { LongValue value = DataValueClasses.newDirectReference(LongValue.class); map.acquireUsing("sequence-" + t, value); long start = System.nanoTime(); int runs = 1000000; for (int i = 0; i < runs; i++) { long nextId = value.addAtomicValue(1); } double rate = (double) (System.nanoTime() - start) / runs; System.out.printf("Uncontended increment took an average of %.1f ns.%n", rate); } // latency test. LongValue value = DataValueClasses.newDirectReference(LongValue.class); map.acquireUsing("sequence-X", value); int runs = 1000000000, count = 0, wcount = 0; long[] worst = new long[200000]; long start = System.nanoTime(); for (; count < runs; count++) { long nextId = value.addAtomicValue(1); long next = System.nanoTime(); long time = next - start; if (time > 100) { worst[wcount++] = time; if (wcount >= worst.length) break; next = System.nanoTime(); } start = next; } Arrays.sort(worst); System.out.printf("Worst 1 in 10K, 1 in 100K, 1 in 1000K, worst is %,d / %,d / %,d / %,d %n", worst[wcount - count / 10000], worst[wcount - count / 100000], worst[wcount - count / 1000000], worst[wcount - 1] ); } } }