Update 6. 从尾到头打印链表.md

题目链接改为力扣中的对应题目,题目描述和代码按该题的接口调整。
This commit is contained in:
CyC2018
2026-10-28 13:45:07 +08:00
parent 4619998f5b
commit 3b095c8ec0
+38 -27
View File
@@ -2,7 +2,7 @@
## 题目链接
[牛客网](https://www.nowcoder.com/practice/d0267f7f55b3412ba93bd35cfa8e8035?tpId=13&tqId=11156&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[Leetcode](https://leetcode.cn/problems/cong-wei-dao-tou-da-yin-lian-biao-lcof/)
## 题目描述
@@ -17,14 +17,22 @@
要逆序打印链表 1-\>2-\>3(3,2,1),可以先逆序打印链表 2-\>3(3,2),最后再打印第一个节点 1。而链表 2-\>3 可以看成一个新的链表,要逆序打印该链表可以继续使用求解函数,也就是在求解函数中调用自己,这就是递归函数。
```java
public ArrayList<Integer> printListFromTailToHead(ListNode listNode) {
ArrayList<Integer> ret = new ArrayList<>();
if (listNode != null) {
ret.addAll(printListFromTailToHead(listNode.next));
ret.add(listNode.val);
}
private ArrayList<Integer> tmp = new ArrayList<>();
public int[] reverseBookList(ListNode head) {
recurse(head);
int[] ret = new int[tmp.size()];
for (int i = 0; i < ret.length; i++)
ret[i] = tmp.get(i);
return ret;
}
private void recurse(ListNode head) {
if (head == null)
return;
recurse(head.next);
tmp.add(head.val);
}
```
### 2. 使用头插法
@@ -33,7 +41,7 @@ public ArrayList<Integer> printListFromTailToHead(ListNode listNode) {
链表的操作需要维护后继关系,例如在某个节点 node1 之后插入一个节点 node2,我们可以通过修改后继关系来实现:
```java
```text
node3 = node1.next;
node2.next = node3;
node1.next = node2;
@@ -48,21 +56,23 @@ node1.next = node2;
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/0dae7e93-cfd1-4bd3-97e8-325b032b716f-1572687622947.gif" width="420px"> </div><br>
```java
public ArrayList<Integer> printListFromTailToHead(ListNode listNode) {
public int[] reverseBookList(ListNode head) {
// 头插法构建逆序链表
ListNode head = new ListNode(-1);
while (listNode != null) {
ListNode memo = listNode.next;
listNode.next = head.next;
head.next = listNode;
listNode = memo;
}
// 构建 ArrayList
ArrayList<Integer> ret = new ArrayList<>();
head = head.next;
ListNode dummy = new ListNode(-1);
int count = 0;
while (head != null) {
ret.add(head.val);
head = head.next;
ListNode memo = head.next;
head.next = dummy.next;
dummy.next = head;
head = memo;
count++;
}
int[] ret = new int[count];
ListNode cur = dummy.next;
int idx = 0;
while (cur != null) {
ret[idx++] = cur.val;
cur = cur.next;
}
return ret;
}
@@ -75,15 +85,16 @@ public ArrayList<Integer> printListFromTailToHead(ListNode listNode) {
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/9d1deeba-4ae1-41dc-98f4-47d85b9831bc.gif" width="340px"> </div><br>
```java
public ArrayList<Integer> printListFromTailToHead(ListNode listNode) {
public int[] reverseBookList(ListNode head) {
Stack<Integer> stack = new Stack<>();
while (listNode != null) {
stack.add(listNode.val);
listNode = listNode.next;
while (head != null) {
stack.push(head.val);
head = head.next;
}
ArrayList<Integer> ret = new ArrayList<>();
int[] ret = new int[stack.size()];
int idx = 0;
while (!stack.isEmpty())
ret.add(stack.pop());
ret[idx++] = stack.pop();
return ret;
}
```