Update 61. 扑克牌顺子.md

题目链接改为力扣中的对应题目，题目描述和代码按该题的接口调整。

notes/61. 扑克牌顺子.md

@@ -2,7 +2,7 @@
 
 ## 题目链接
 
-[NowCoder](https://www.nowcoder.com/practice/762836f4d43d43ca9deb273b3de8e1f4?tpId=13&tqId=11198&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
+[Leetcode](https://leetcode.cn/problems/bu-ke-pai-zhong-de-shun-zi-lcof/)
 
 ## 题目描述
 
@@ -14,24 +14,23 @@
 ## 解题思路
 
 ```java
-public boolean isContinuous(int[] nums) {
-
-    if (nums.length < 5)
+public boolean checkDynasty(int[] places) {
+    if (places == null || places.length < 5)
         return false;
 
-    Arrays.sort(nums);
+    Arrays.sort(places);
 
     // 统计癞子数量
     int cnt = 0;
-    for (int num : nums)
-        if (num == 0)
+    for (int place : places)
+        if (place == 0)
             cnt++;
 
     // 使用癞子去补全不连续的顺子
-    for (int i = cnt; i < nums.length - 1; i++) {
-        if (nums[i + 1] == nums[i])
+    for (int i = cnt; i < places.length - 1; i++) {
+        if (places[i + 1] == places[i])
             return false;
-        cnt -= nums[i + 1] - nums[i] - 1;
+        cnt -= places[i + 1] - places[i] - 1;
     }
 
     return cnt >= 0;