Update 13. 机器人的运动范围.md

题目链接改为力扣中的对应题目，题目描述和代码按该题的接口调整。

notes/13. 机器人的运动范围.md

@@ -1,6 +1,6 @@
 # 13. 机器人的运动范围
 
-[牛客网](https://www.nowcoder.com/practice/6e5207314b5241fb83f2329e89fdecc8?tpId=13&tqId=11219&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
+[Leetcode](https://leetcode.cn/problems/ji-qi-ren-de-yun-dong-fan-wei-lcof/)
 
 ## 题目描述
 
@@ -14,20 +14,20 @@
 
 ```java
 private static final int[][] next = {{0, -1}, {0, 1}, {-1, 0}, {1, 0}};
-private int cnt = 0;
+private int res = 0;
 private int rows;
 private int cols;
 private int threshold;
 private int[][] digitSum;
 
-public int movingCount(int threshold, int rows, int cols) {
-    this.rows = rows;
-    this.cols = cols;
-    this.threshold = threshold;
+public int wardrobeFinishing(int m, int n, int cnt) {
+    this.rows = m;
+    this.cols = n;
+    this.threshold = cnt;
     initDigitSum();
     boolean[][] marked = new boolean[rows][cols];
     dfs(marked, 0, 0);
-    return cnt;
+    return res;
 }
 
 private void dfs(boolean[][] marked, int r, int c) {
@@ -36,7 +36,7 @@ private void dfs(boolean[][] marked, int r, int c) {
     marked[r][c] = true;
     if (this.digitSum[r][c] > this.threshold)
         return;
-    cnt++;
+    res++;
     for (int[] n : next)
         dfs(marked, r + n[0], c + n[1]);
 }