Update 35. 复杂链表的复制.md

题目链接改为力扣中的对应题目,题目描述和代码按该题的接口调整。
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CyC2018
2026-10-28 13:45:05 +08:00
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# 35. 复杂链表的复制
[NowCoder](https://www.nowcoder.com/practice/f836b2c43afc4b35ad6adc41ec941dba?tpId=13&tqId=11178&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[Leetcode](https://leetcode.cn/problems/fu-za-lian-biao-de-fu-zhi-lcof/)
## 题目描述
输入一个复杂链表(每个节点中有节点值,以及两个指针,一个指向下一个节点,另一个特殊指针指向任意一个节点),返回结果为复制后复杂链表的 head。
```java
public class RandomListNode {
int label;
RandomListNode next = null;
RandomListNode random = null;
class Node {
int val;
Node next;
Node random;
RandomListNode(int label) {
this.label = label;
public Node(int val) {
this.val = val;
this.next = null;
this.random = null;
}
}
```
@@ -35,33 +37,33 @@ public class RandomListNode {
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/e151b5df-5390-4365-b66e-b130cd253c12.png" width="600"/> </div><br>
```java
public RandomListNode Clone(RandomListNode pHead) {
if (pHead == null)
public Node copyRandomList(Node head) {
if (head == null)
return null;
// 插入新节点
RandomListNode cur = pHead;
Node cur = head;
while (cur != null) {
RandomListNode clone = new RandomListNode(cur.label);
Node clone = new Node(cur.val);
clone.next = cur.next;
cur.next = clone;
cur = clone.next;
}
// 建立 random 链接
cur = pHead;
cur = head;
while (cur != null) {
RandomListNode clone = cur.next;
Node clone = cur.next;
if (cur.random != null)
clone.random = cur.random.next;
cur = clone.next;
}
// 拆分
cur = pHead;
RandomListNode pCloneHead = pHead.next;
cur = head;
Node cloneHead = head.next;
while (cur.next != null) {
RandomListNode next = cur.next;
Node next = cur.next;
cur.next = next.next;
cur = next;
}
return pCloneHead;
return cloneHead;
}
```