Update 42. 连续子数组的最大和.md

题目链接改为力扣中的对应题目,题目描述和代码按该题的接口调整。
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# 42. 连续子数组的最大和
[NowCoder](https://www.nowcoder.com/practice/459bd355da1549fa8a49e350bf3df484?tpId=13&tqId=11183&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[Leetcode](https://leetcode.cn/problems/lian-xu-zi-shu-zu-de-zui-da-he-lcof/)
## 题目描述
@@ -9,12 +9,12 @@
## 解题思路
```java
public int FindGreatestSumOfSubArray(int[] nums) {
if (nums == null || nums.length == 0)
public int maxSales(int[] sales) {
if (sales == null || sales.length == 0)
return 0;
int greatestSum = Integer.MIN_VALUE;
int sum = 0;
for (int val : nums) {
for (int val : sales) {
sum = sum <= 0 ? val : sum + val;
greatestSum = Math.max(greatestSum, sum);
}