Update 28. 对称的二叉树.md

题目链接改为力扣中的对应题目,题目描述和代码按该题的接口调整。
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CyC2018
2026-10-28 13:45:04 +08:00
parent c863a8a23d
commit d91f3fd377
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@@ -1,6 +1,6 @@
# 28. 对称的二叉树
[NowCoder](https://www.nowcoder.com/practice/ff05d44dfdb04e1d83bdbdab320efbcb?tpId=13&tqId=11211&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[Leetcode](https://leetcode.cn/problems/dui-cheng-de-er-cha-shu-lcof/)
## 题目描述
@@ -9,19 +9,19 @@
## 解题思路
```java
boolean isSymmetrical(TreeNode pRoot) {
if (pRoot == null)
public boolean checkSymmetricTree(TreeNode root) {
if (root == null)
return true;
return isSymmetrical(pRoot.left, pRoot.right);
return checkSymmetricTree(root.left, root.right);
}
boolean isSymmetrical(TreeNode t1, TreeNode t2) {
private boolean checkSymmetricTree(TreeNode t1, TreeNode t2) {
if (t1 == null && t2 == null)
return true;
if (t1 == null || t2 == null)
return false;
if (t1.val != t2.val)
return false;
return isSymmetrical(t1.left, t2.right) && isSymmetrical(t1.right, t2.left);
return checkSymmetricTree(t1.left, t2.right) && checkSymmetricTree(t1.right, t2.left);
}
```